Generate own link instead of pagination render default link - laravel 5.0

Developed one new laravel 5.0 app. There I have used ajax concept for every pages. Each and every request and response will travel through ajax.

Navigation Link:

<li onclick="view('bydproject')"><a>View ByDProject Data </a></li>

Ajax call :

function view(url)
  {
      fullurl = "http://localhost:8000/" + url ;
      var xhttp = new XMLHttpRequest();
      xhttp.onreadystatechange = function(){
      if(xhttp.readyState == 4 && xhttp.status == 200)
      {
        document.getElementById("main").innerHTML = xhttp.responseText;
      }
    };
    xhttp.open("GET", fullurl, true);
    xhttp.send();
   }

In one of the case, I have used pagination concept for some page.

Conctroller:

$employees = ByDEmployee::where('first_name' , 'LIKE', '%'.$Data.'%')->paginate(20);
return view('bydemployee.view_all_employees', compact('employees'));

In this situation pagination render link generate that own link. instead of that link I have to generate my ajax call? whether it is possible ?

Ex: Instaed of this

<li><a href="http://localhost:8000/bydemployee?page=2" rel="prev">&laquo;</a></li> 

Link looks like this

<li><a onclick=view('bydemployee?page=2') rel="prev">&laquo;</a></li> 

via Chebli Mohamed