This is my code
var feetype="";
console.log(feetype);
Works perfectly fine. However when I try to modify it like so
var fee_type_id = 2;
var feetype="";
console.log(feetype);
It throws the following error
Use of undefined constant fee_type_id - assumed 'fee_type_id' (this will throw an Error in a future version of PHP)
What am I doing wrong?
via Chebli Mohamed
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