Hi am trying to send my ajax value into my php field but when i try to make changes i always gets the blank input field
this is my form
<div id="paymentDetail" style="display: none">
<center>
$count=0;
<form method="post" action="">
@foreach($product as $input)
<div>Product: <span class="product"><input type="text" name="product[]" value=""></span></div>
<div>paymentID: <input type="text" class="paymentID" name="txn_id" value=""></div>
<div>paymentDate: <span class="paymentDate" name="date"></span></div>
@endforeach
<div>Print: <span><input type="submi" name="print" value="Print Order Summary"></span></div>
</form>
</center>
</div>
this is the script i am using
function demoSuccessHandler(transaction) {
// You can write success code here. If you want to store some data in database.
$("#paymentDetail").removeAttr('style');
$('.paymentID').value(transaction.razorpay_payment_id);
var paymentDate = new Date();
$('.paymentDate').text(
padStart(paymentDate.getDate()) + '.' + padStart(paymentDate.getMonth() + 1) + '.' + paymentDate.getFullYear() + ' ' + padStart(paymentDate.getHours()) + ':' + padStart(paymentDate.getMinutes())
);
$.ajax({
method: 'post',
url: "{!!route('dopayment')!!}",
data: {
"_token": "",
"razorpay_payment_id": transaction.razorpay_payment_id
},
complete: function (r) {
console.log('complete');
console.log(r);
}
})
}
via Chebli Mohamed
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